Ecc0
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well..both, electrical and mechanical, drain energy from same source and it is crankshaft (during motion)...if that is true, then we also need to assume that certain air mass flow need to produce to cool down engine..force necessary to produce such flow is final force..
so, in case of electrical fan equation will be something like this
FF=frictionBelt_Dynamo_crankShaft+(Electrical Energy Produced By Dynamo For Fan)+(electrical resistance for all wiring related to fan including all bearings on fan and support electronics)+(Air Flow force)+(inertial momentum of fan every time it starts)
In case of mechanical fan, because its attached directly to crankshaft there is no energy transfer in between but this:
FF=Air Flow Force + inertial momentum of fan at startup(once)
..point is that energy transfer is never 1:1. in which case electrical will use less energy..its alwys less that 1:1, so mechanical is closer to that ratio as less energy transfer happening in between..
so, in case of electrical fan equation will be something like this
FF=frictionBelt_Dynamo_crankShaft+(Electrical Energy Produced By Dynamo For Fan)+(electrical resistance for all wiring related to fan including all bearings on fan and support electronics)+(Air Flow force)+(inertial momentum of fan every time it starts)
In case of mechanical fan, because its attached directly to crankshaft there is no energy transfer in between but this:
FF=Air Flow Force + inertial momentum of fan at startup(once)
..point is that energy transfer is never 1:1. in which case electrical will use less energy..its alwys less that 1:1, so mechanical is closer to that ratio as less energy transfer happening in between..