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<blockquote data-quote="t2ribena" data-source="post: 601668" data-attributes="member: 3847"><p>seriously, what is the funtion of FF you are trying to derive?</p><p></p><p>if you are actually calculating the energy required to feed the system then, your equation is flawed. One simple one is, the alternator drag still exist even if u have only the mechanical fan...the friction on the alternator does not change according to electrical load significantly as it is a electromagnetic drive system...as the electrical fan is decoupled from the crank, you did not factored in the drag on the mechanical fan created during its operation which is not negligible as it is directly driven by the crank...</p><p></p><p>by the way? the function of the fan is to push the air in order for massive amount of air to pass thru the heat exchanger or what we know as the radiator...not to primarily 'blow' the engine cool as it is not an efficient method to cool engine, the water to air via heat exchanger is more efficient...</p></blockquote><p></p>
[QUOTE="t2ribena, post: 601668, member: 3847"] seriously, what is the funtion of FF you are trying to derive? if you are actually calculating the energy required to feed the system then, your equation is flawed. One simple one is, the alternator drag still exist even if u have only the mechanical fan...the friction on the alternator does not change according to electrical load significantly as it is a electromagnetic drive system...as the electrical fan is decoupled from the crank, you did not factored in the drag on the mechanical fan created during its operation which is not negligible as it is directly driven by the crank... by the way? the function of the fan is to push the air in order for massive amount of air to pass thru the heat exchanger or what we know as the radiator...not to primarily 'blow' the engine cool as it is not an efficient method to cool engine, the water to air via heat exchanger is more efficient... [/QUOTE]
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