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Message: <blockquote data-quote="jarance" data-source="post: 519176" data-attributes="member: 21">65mA x 24 hours = 1.56 AH per day. Assuming that your battery is 60 AH, that means that your battery would be drained completely = 60 AH/1.56 = 38 days i.e. 12 VDC to 0 VDC.(of course assuming the discharge is linear but it is not)25 to 50mA (average 30 mA) x 24 hours = 0.72 AH per day. Assuming that your battery is 60 AH, that means that your battery would be drained completely = 60 AH/0.72 = 72 days i.e. 12 VDC to 0 VDC.(of course assuming the discharge is linear but it is not). This (72 days) is almost double the number of days.so check the milliamp when the kenwood HU fuse is disconnect lor.In reality, the starter will not cranked properly if the battery voltage dropped below 10.5 VDC. or below 85% of the nominal voltage.</blockquote>